What is the oxidation number for Ag3PO4?

The oxidation number of silver (Ag) is +1 and the oxidation number of oxygen (O) is -2. To find the oxidation number of phosphorus (P) in Ag3PO4, we can set up an equation: 3(+1) + x + 4(-2) = 0. Solving for x, we find that the oxidation number of phosphorus in Ag3PO4 is +5.