what if 125 cal of heat is applied to a 60.0 g piece of copper at 22.0 c to 60.0 c what will the final temperature be the specific heat of copper is 0920 cal g c?

To find the final temperature of the copper after applying 125 cal of heat, we can use the formula: ( q = mc\Delta T ), where ( q ) is the heat added, ( m ) is the mass, ( c ) is the specific heat, and ( \Delta T ) is the change in temperature. Rearranging the formula gives us ( \Delta T = \frac{q}{mc} ). Plugging in the values: ( \Delta T = \frac{125 , \text{cal}}{60.0 , \text{g} \times 0.0920 , \text{cal/g°C}} \approx 22.6°C ). Therefore, the final temperature will be approximately ( 22.0°C + 22.6°C \approx 44.6°C ).