Find three consecutive odd integers such that the sum of the first twice the second and three times the third is 70?

Let x, x+2 and x+4 be the three consecutive odd integers. x+2(x+2)+3(x+4)=70 x+2x+4+3x+12=70 6x+16=70 6x=54 x=9 The numbers are 9, 11, and 13 Check: 9+2(11)+3(13)= 9+22+39=70