The expression ( e^{i \pi} + 1 ) is derived from Euler's formula, which states that ( e^{ix} = \cos(x) + i \sin(x) ). Specifically, when ( x = \pi ), this simplifies to ( e^{i \pi} = -1 ). Therefore, ( e^{i \pi} + 1 = -1 + 1 = 0 ). Thus, the answer is 0.
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