The reaction between baking soda (NaHCO₃) and acetic acid (CH₃COOH) can be represented by the balanced equation:
[ \text{NaHCO}_3 + \text{CH}_3\text{COOH} \rightarrow \text{CH}_3\text{COONa} + \text{H}_2\text{O} + \text{CO}_2 ]
From the equation, one mole of baking soda reacts with one mole of acetic acid. To find the stoichiometric amounts, first calculate the moles of NaHCO₃ in 10 grams (approximately 0.119 moles), and then use the same mole ratio to determine the amount of acetic acid needed. Given that the concentration of vinegar is 5 M, you would need around 0.119 moles of acetic acid, which corresponds to about 23.8 mL of vinegar.
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