A bag contains 3 blue disks 3 green disks and 4 orange disks. If three disks are selected random from the bag what is the probability that 1 of the disks will be green and the other 2 of the disks wil?

To find the probability of selecting 1 green disk and 2 disks of another color from the bag, we first calculate the total number of ways to choose 3 disks from the 10 disks (3 blue, 3 green, and 4 orange) in the bag, which is ( \binom{10}{3} = 120 ). Next, we calculate the number of ways to choose 1 green disk (from 3) and 2 disks of any other color (from 7 non-green disks), which can be done in ( \binom{3}{1} \times \binom{7}{2} = 3 \times 21 = 63 ). The probability is then given by the ratio of successful outcomes to total outcomes: ( \frac{63}{120} = \frac{21}{40} ). Thus, the probability is ( \frac{21}{40} ).