How many moles of atoms are in a pure gold ring (24K) that has a mass of 6.62 g?

1 answer

Answer

1126739

2026-04-12 13:35

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First you have to convert mmol to mol,

0.0102/1000=1.02*10^-5 mol.

Second, multiply the mol by avogadro's number (6.022*10^23)

(1.02*10^-5)*(6.022*10^23)=6.14244*10^18

Third and last, Round to 3 sig figs

6.14*10^18

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