What is the probability you will select 2 red marbles if you have 3 red marbles and 1 green marble in a bag You draw 1 marble and without putting it back you draw a 2nd one?

To find the probability of selecting 2 red marbles without replacement, first consider the total number of marbles, which is 4 (3 red and 1 green). The probability of drawing the first red marble is ( \frac{3}{4} ). After drawing the first red marble, there are now 2 red marbles left out of 3 total marbles, making the probability of drawing a second red marble ( \frac{2}{3} ). Therefore, the combined probability of both events is ( \frac{3}{4} \times \frac{2}{3} = \frac{1}{2} ) or 50%.