How much hydrochloric acid in grams can be neutralized by 4.00 g of sodium bicarbonate (Hint Begin by writing a balanced equation for the reaction between aqueous sodium bicarbonate and aqueous hydroc?

The balanced equation for the reaction between sodium bicarbonate (NaHCO₃) and hydrochloric acid (HCl) is:

[ \text{NaHCO}_3 (aq) + \text{HCl} (aq) \rightarrow \text{NaCl} (aq) + \text{H}_2\text{O} (l) + \text{CO}_2 (g) ]

From the equation, one mole of sodium bicarbonate reacts with one mole of hydrochloric acid. The molar mass of sodium bicarbonate is approximately 84.01 g/mol, so 4.00 g of NaHCO₃ is about 0.0475 moles. Therefore, it can neutralize an equivalent amount of HCl, which is approximately 1.74 g (using the molar mass of HCl, about 36.46 g/mol).