If you can use the numbers 1, 2, 3, and 4 to create a passWord of length 4, and if repetition is allowed, there are (4^4 = 256) possible combinations. If the digits cannot be repeated, the number of possible passWords would be (4! = 24) (which is 4 factorial). Therefore, the total number of passWords depends on whether repetition is allowed or not.
Copyright © 2026 eLLeNow.com All Rights Reserved.