How do you draw a rectangle with a perimeter of 12 units and an area equalling 8?

P = 12 = 2( l + w)

A = 8 = l*w.

Hence

6 = l + w

8 = l X w

It follows

w = 6 - l

Substitute

8 = l X ( 6 - l

Myltiply out

8 = 6l - l^(2)

l^(2) - 6l + 8 = 0

It is now in Quadratic form ; Factor

(l -4)( l -2) = 0

Hence ;(length) = 4

Widt = 2 .