What is two consecutive odd integers whose product is 1599?

Let the two consecutive odd integers be ( x ) and ( x + 2 ). The equation for their product is ( x(x + 2) = 1599 ). Expanding this gives ( x^2 + 2x - 1599 = 0 ). Solving this quadratic equation, we find that the integers are 39 and 41, as their product equals 1599.