From a balloon ascending with a velocity of 32 feet per second a stone was dropped and it reached the ground in 11 seconds how high was the balloon when the stone was dropped?

The general formula for distance traveled under uniform acceleration is:

S = v0t + at2 / 2

In our case, the initial velocity is in opposite direction that acceleration.

Let's choose a direction of our axis of displacement: let it face downwards. In this coordinate system, v0 will be

v0 = -9.75 m/s (converted from 32 ft/s)

a = g = 9.81 m/s2

Our formula will then take form:

S = -9.75 * 11 + 9.81 * 112 / 2 = 486.26 m

or in feet: S = 1595.32 ft