How much oxygen is required if C2H6 O2 CO2 H2O if 7.85 mil of ethane?

The combustion of ethane (C₂H₆) can be represented by the balanced equation: 2 C₂H₆ + 7 O₂ → 4 CO₂ + 6 H₂O. From this equation, it can be seen that 2 moles of ethane require 7 moles of oxygen. Therefore, for 7.85 moles of ethane, the required oxygen would be (7 O₂ / 2 C₂H₆) × 7.85 C₂H₆ = 27.48 moles of O₂.