How many molecules (not moles) of NH3 are produced from 5.69104 g of H2?

The reaction would be H2 + 3N2 ==>2NH3
moles H2 used = 5.69104 g x 1 mole/2.00 = 2.84552 moles H2
moles NH3 produced (assuming N2 is NOT limiting) = 2 moles NH3/mole H2 x 2.84552 moles H2 = 5.69104 moles NH3 produced
Molecules of NH3 produced = 5.69104 moles x 6.02x10^23 molecules/mole = 3.4x10^24 molecules