This is algebra.
Let's take 2 numbers, x and y. What we want is xy = -120 and x+y = -14.
So we have two equations. Let's solve for one of the numbers and move that over to the other equation.
x+y=-14
x=-14-y
Let us now plug that x into the other equation.
(-14-y)y=-120
We now distribute the y to both -14 and -y.
-14y-y^2=-120
moving everything to one side we get
0=y^2+14y-120
now it's just a matter of solving for y, which can be found using the quadratic equation (-b+-(b^2-4ac)^(1/2))/(2a), where a=1, b=14, and c=-120.
Let's try plus first
(-14+(14^2-(4)(-120))^(1/2))/2
(-14+(196+480)^(1/2))/2
(-14+26)/2
6
so y=6. Let's plug that into one of the equations we had, x+y=-14.
x+6=-14
x=-20
To see if this works, let's try y=6 and x=-20 on both equations
-20(6)=-120
-20+6=-14
They work!
By the way, if we had tried minus in the quadratic equation, we would've gotten -20 for y and x as 6.
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