The perimeter of a rectangle is 124 inches the length exceeds the width by 28 inches find the length and the width?

Here is what we are given:

1. 2L + 2W = 184

2. L = W + 32

Since we know L in terms of W, we can substitute equation (2) into equation (1), and solve for W:

3. 2(W+32) + 2W = 184

4. 2W + 64 + 2W = 184

5. 4W + 64 = 184

6. 4W = 120

7. W = 30

Now we know the width, substitute this back into equation (2):

8. L = 30+ 32

9. L = 62

Now check the result by substituting these values into equation (1):

10. 2(62) + 2(30) = 184

11. 124 + 60 = 184

12. 184 = 184

QED