To find the empirical formula of hydrated magnesium bromide, we first determine the moles of magnesium (Mg), bromine (Br), and water (H₂O) after heating. The mass of anhydrous magnesium bromide is 8.95g - 2.03g = 6.92g. The moles of water lost (2.03g) is calculated as 2.03g / 18.02g/mol = 0.112 moles. Assuming magnesium bromide has the formula MgBr₂, we find the moles of Mg and Br in the remaining mass, leading to an empirical formula of MgBr₂·xH₂O, where x is determined by the ratio of moles of water to moles of MgBr₂.
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