How do you balance fe2o3 plus hno3 plus fe no3 3 plus H2O?

Step 1: Count elements on both sides

Left: Fe = 2, O = 3 (from Fe₂O₃) + 3 (from 3 HNO₃) = ?, need to fix.

Right: Fe = 1 (in Fe(NO₃)₃) → we’ll need 2 of those.

Step 2: Balance Fe

Fe2O3+HNO3→2Fe(NO3)3+H2OFe_2O_3 + HNO_3 \rightarrow 2Fe(NO_3)_3 + H_2OFe2​O3​+HNO3​→2Fe(NO3​)3​+H2​O

Now Fe is balanced (2 each side).

Step 3: Balance NO₃ groups and H

Each Fe(NO₃)₃ has 3 nitrate groups, and there are 2 Fe(NO₃)₃ → total 6 nitrate ions.

So, we need 6 HNO₃ on the left.

Fe2O3+6HNO3→2Fe(NO3)3+3H2OFe_2O_3 + 6HNO_3 \rightarrow 2Fe(NO_3)_3 + 3H_2OFe2​O3​+6HNO3​→2Fe(NO3​)3​+3H2​O

✅ Balanced Equation:

Fe2O3+6HNO3→2Fe(NO3)3+3H2O\boxed{Fe_2O_3 + 6HNO_3 \rightarrow 2Fe(NO_3)_3 + 3H_2O}Fe2​O3​+6HNO3​→2Fe(NO3​)3​+3H2​O​