Two satellites are in orbit around planet one satellite has an orbital radius of 8.0 10 6 mthe period of revolution of this satellite is 1.0 10 6 sthe other satellite has an orbit radius of 2.0 10 7 m?

To find the period of revolution of the second satellite, we can use Kepler's Third Law, which states that the square of the orbital period (T) is proportional to the cube of the orbital radius (r): (T^2 \propto r^3). For the first satellite, (T_1^2 = (1.0 \times 10^6 , s)^2) and (r_1 = 8.0 \times 10^6 , m). For the second satellite with (r_2 = 2.0 \times 10^7 , m), we can set up the ratio ((T_2^2 / T_1^2) = (r_2^3 / r_1^3)) and solve for (T_2), leading to (T_2 \approx 2.52 \times 10^6 , s).