Find two numbers whose sum is 64 and whose difference is 12?

Let's denote the two numbers as x and y. From the given conditions, we can write the equations x + y = 64 and x - y = 12. By solving these two equations simultaneously, we can find the values of x and y. Adding the two equations eliminates y, giving 2x = 76, so x = 38. Substituting x back into one of the equations gives y = 26. Therefore, the two numbers are 38 and 26.