How do you write a program in java to check a number is neon number?

Java

1 answer

Answer

1153026

2026-07-29 23:35

+ Follow

class neonn

{

; public static void check()throws IOException

; {

; BufferedReader br = new BufferedReader ( new InputStreamReader(System.in));

; int num;

; System.out.println("Enter the number to be checked!");

; num=Integer.parseInt(br.readLine());

; int square;

; square=num*num; //squaring the number

;

; int sum=0;

;

; String sqs=Integer.toString(square);

; for(int i=0; i<sqs.length(); i++)

; sum+=Integer.parseInt(sqs.substring ( i,i+1 ) ) ;

;

; if (sum==num) //checking if the sum of the square is equal to the number entered

; System.out.println(num+" is a Neon Number!"); // if yes. It is neon

; else

; System.out.println(num+" is not a Neon number!"); //otherwise not

;

; }

;

}

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