To find the number of linear arrangements of the letters in "CALL," we first note that there are 4 letters in total, with the letter 'L' repeated twice. The formula for the arrangements of letters where some are repeated is given by ( \frac{n!}{p_1! \cdot p_2! \cdots p_k!} ), where ( n ) is the total number of letters, and ( p_1, p_2, \ldots, p_k ) are the frequencies of the repeated letters.
In this case, we have:
Thus, the number of arrangements is:
[ \frac{4!}{2!} = \frac{24}{2} = 12 ]
Therefore, there are 12 distinct linear arrangements of the letters in "CALL."
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