What is the length of side c if side b equals 20 Angle A equals 43 degrees and angle C equals 72 degrees?

In a triangle a/SinA = b/SinB = c/SinC

Since angle A = 43 and angle C is 72, angle B = (180) - (72 + 43) = 65

Hence 20/Sin65 = c/Sin72

20/0.9063 = c/0.9510

c = (20 x 0.9510)/0.9063 = 20.9864