What is the first four terms of the sequence ann(2n-8)?

To find the first four terms of the sequence defined by ( a_n = 2n - 8 ), we can substitute ( n = 1, 2, 3, ) and ( 4 ).

1. For ( n = 1 ): ( a_1 = 2(1) - 8 = 2 - 8 = -6 )
2. For ( n = 2 ): ( a_2 = 2(2) - 8 = 4 - 8 = -4 )
3. For ( n = 3 ): ( a_3 = 2(3) - 8 = 6 - 8 = -2 )
4. For ( n = 4 ): ( a_4 = 2(4) - 8 = 8 - 8 = 0 )

Thus, the first four terms of the sequence are (-6, -4, -2, 0).