How much charge is on each plate of a 12.7mf capacitor that has been charged by 120.0 V potential difference?

To find the charge on each plate of a capacitor, use the formula ( Q = C \times V ), where ( Q ) is the charge, ( C ) is the capacitance, and ( V ) is the potential difference. For a 12.7 µF (microfarads) capacitor charged to 120.0 V, first convert capacitance to farads: ( 12.7 , \text{µF} = 12.7 \times 10^{-6} , \text{F} ). Then, calculate the charge: ( Q = 12.7 \times 10^{-6} , \text{F} \times 120.0 , \text{V} = 1.524 , \text{mC} ) (milliCoulombs). Thus, each plate has a charge of approximately 1.524 mC.