A flashlight uses batteries that add up to 3.0V and has a power output of 0.50 W what is the effective resistance of the flashlight?

1 answer

Answer

1080781

2026-07-13 08:25

+ Follow

a) Current = (.5/3) = .166A (166mA).


b) Effective resistance = (3/.166) = 18.07 ohms.

ReportLike（0）ShareFavorite

Related Questions

Topics to Explore

InstagramTumblrSkypePhotoshopPowerPointPostgreSQLMySQLJavaScriptJavaLinuxStarlinkSpaceXDELLYahoogoogleAndroidExcelMicrosoftWordTikTokAppleiOSiphoneipadWindowsYouTubeAmazon

A-Z Search

ABCDEFGHIJKLMNOPQRSTUVWXYZ0-9

About Us|Disclaimer|Copyright Notice|Infringement Report|Privacy Policy|Contact Us

Copyright © 2026 eLLeNow.com All Rights Reserved.