What is the solution to the recurrence relation t(n) t(n-2) n2, and how does it relate to the overall pattern of the sequence?

The solution to the recurrence relation t(n) t(n-2) n2 is t(n) n2 (n-2)2 (n-4)2 ... 42 02. This relation shows that each term in the sequence is the square of the corresponding even number, starting from n. The overall pattern of the sequence is that it consists of the squares of even numbers in descending order, with each term being the square of the previous even number.