What is the molalaity of a solution made by dissolving 2 of NaOH in 6 kg of water?

To calculate the molality of a solution, you need to know the number of moles of solute and the mass of the solvent in kilograms. The molar mass of NaOH is approximately 40 g/mol, so 2 grams of NaOH corresponds to 0.05 moles (2 g ÷ 40 g/mol). Given that the mass of the solvent (water) is 6 kg, the molality (m) is calculated as moles of solute divided by kilograms of solvent: ( m = \frac{0.05 , \text{moles}}{6 , \text{kg}} \approx 0.00833 , \text{mol/kg} ).