What is the expected hybridization of the central atom of ICl3?

In icl3 central atom is iodine and its valency is 7 out of 7 electrons 3 electrons are in chemical bonding so 2 lone pairs are there.

Hybridization = number of sigma bonds + number of lone pairs = 3 sigma bonds + 2 lone pairs = 5 = sp3d ( 1 s + 3 P + 1 d = 5 ).