How procedure of NaoH are required to prepare 0.25 L of 0.5 M of solution?

Oh, dude, to prepare 0.25 L of 0.5 M NaOH solution, you would need to use the formula M1V1 = M2V2. So, you'd need to calculate the volume of stock NaOH solution (which is probably 1 M) you need to dilute with water to get the desired concentration. It's like a chemistry magic trick, but with more measuring cups.