What volume of water can be boiled by 3.0kJ of energy?

To determine the volume of water that can be boiled by 3.0 kJ of energy, we first need to know the amount of energy required to boil water. The latent heat of vaporization of water is approximately 2260 kJ/kg. Therefore, the volume of water that can be boiled is calculated as follows:

[ \text{mass} = \frac{3.0 \text{ kJ}}{2260 \text{ kJ/kg}} \approx 0.00133 \text{ kg} ]

Since the density of water is about 1 kg/L, this corresponds to approximately 1.33 mL of water that can be boiled with 3.0 kJ of energy.