An airplane flies from its home airport to a city and back in 5hrs flryjng time. The plane travels the 720 mi to the city at 295 mih with no wind. How strong is the wind on the return fight?

The airplane travels 720 miles to the city at a speed of 295 mph, taking approximately 2.44 hours (720 mi ÷ 295 mph). The total round trip time is 5 hours, so the return flight must take about 2.56 hours (5 hrs - 2.44 hrs). If we let the wind speed be ( w ), the return speed becomes ( 295 - w ). Thus, the equation for the return flight is ( 720 = (295 - w) \times 2.56 ). Solving for ( w ) gives a wind speed of approximately 34.84 mph.