To determine if the equation (2 \text{Al} + 6 \text{NaOH} \rightarrow 2 \text{Na}_3\text{AlO}_3 + 2 \text{H}_2) is balanced, we need to compare the number of each type of atom on both sides. On the left, there are 2 aluminum (Al), 6 sodium (Na), and 6 oxygen (O) atoms, while on the right, there are 6 sodium, 2 aluminum, 6 oxygen, and 4 hydrogen (H) atoms. The number of hydrogen atoms is not equal; thus, the equation is not balanced.
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