How many grams of Ba(CH3COO)2 are there in 237 grams of an aqueous solution that is 25.7 by weight Ba(CH3COO)2.?

To find the grams of Ba(CH3COO)2 in the solution, calculate the mass of Ba(CH3COO)2 using the percentage data (25.7%) provided.

Mass of Ba(CH3COO)2 in 237 g solution = 237 g x 25.7% = 60.99 g

Therefore, there are 60.99 grams of Ba(CH3COO)2 in the solution.