If the distance between the point 5-3 and x 1 is 5 units find x?

Final solution, x = 2 ----- WORK -----

(5, -3) (X2, 1)

(X1, Y1) (X2, Y2)

D = SQRT( [X1 - X2]2 + [Y1 - Y2]2 )

5 = SQRT( [5 - X2]2 + [-3 - 1]2 )

5 = SQRT( [5 - X2]2 + (-4)2 )

5 = SQRT( [5 - X2]2 + 16 )

Since The square root of 25 is 5, we know that ->

[5 - X2]2 + 16 = 25

Subtract 16 from both sides,

[5 - X2]2 = 9

Which means that 5-X2 = 3 Because 32 is 9

5 - X2 = 3

subtract 5 from both sides

-X2 = -2

multiply both sides by -1

X2 = 2

There you go...

X2 = 2

(5, -3) (2, 5)