What is the of angle if the measure of its complement is 10 more than twice its measure?

Let the angle be ( x ). The complement of the angle is ( 90 - x ). According to the problem, the complement is equal to ( 10 + 2x ). Setting up the equation, we have ( 90 - x = 10 + 2x ). Solving for ( x ), we get ( 90 - 10 = 3x ) or ( 80 = 3x ), leading to ( x = \frac{80}{3} ) or approximately ( 26.67 ) degrees.