What is the molarity of a solution that contains 612 grams of CaCl2 in 3.04 liters of solution?

To find the molarity, first calculate the number of moles of CaCl2. The molar mass of CaCl2 is approximately 110.98 g/mol. Thus, 612 grams of CaCl2 is about ( \frac{612 , \text{g}}{110.98 , \text{g/mol}} \approx 5.52 , \text{mol} ). The molarity (M) is then calculated as moles of solute divided by liters of solution: ( M = \frac{5.52 , \text{mol}}{3.04 , \text{L}} \approx 1.81 , \text{M} ).