What is the width of a rectangle who has 222 millimeters as the perimeter and a length of 60 millimeters?

For

P = perimeter

L = length

W = width

2L + 2W = P

For the given information this means

2x60 + 2W = 222

120 + 2W = 222

2W = 222

W = 51

So the Width would be 51 millimeters