First, find the moles of NaCl.
Because you have 400 milligrams of NaCl convert to grams by dividing 1000mg. 400mg/1000mg = 0.400 grams of NaCl.
Now we need to convert to moles. For every mole of NaCl there is 58.44 grams. (22.99g Na + 35.45 g Cl) so using stoichiometry (grams cancel) I get .0068 moles of NaCl.
Conver 100 mL to L by dividing by 1000mL. Therefore there is .001 L in the solution.
Molarity is moles per Liter. So 0.0068 mols of NaCl / 0.001 L = 6.84 M
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