What is the area of rhombus DEFG if DF equals 10 and EG equals 11?

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1279557

2026-07-21 11:16

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The diagonals of a rhombus are perpendicular to each other and bisect one another. So you can consider the diagonals dividing the rhombus into 4 identical, right-angled triangles where the sides subtending the right angle are of length 10/2 and 11/2. The area of each of these triangles is 1/2 * 10/2 * 11/2 = 110/8 There are 4 such triangles, so their combined area is 4 * 110 / 8 = 110 / 2 = 55 square units.

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