If y varies inversely as x and y 5 when x 2 find x when y is 4?

Since ( y ) varies inversely as ( x ), we can express this relationship as ( y = \frac{k}{x} ), where ( k ) is a constant. Given that ( y = 5 ) when ( x = 2 ), we can find ( k ) by substituting these values: ( 5 = \frac{k}{2} ), which gives ( k = 10 ). Now, to find ( x ) when ( y = 4 ), we set up the equation ( 4 = \frac{10}{x} ). Solving for ( x ) gives ( x = \frac{10}{4} = 2.5 ).