The perimeter of a rectangular garden is 98 feet The length of the garden is 4 feet more than twice the width What is the length of the garden?

To solve this problem using algebraic equations :

Set the variable x as the width of the garden

The length of the garden becomes 2x + 4 (4 feet more than twice X).

The perimeter is equal to twice the length plus twice the width P = 2L + 2W

and has the value 98 feet.

Substituting the terms for length and width,

98 = 2 L + 2 W so 2(2x+4) + 2(x) = 98

2(2x+4) + 2 (x) = 98

4x + 8 + 2x = 98

6x = 90

x = 15 and 2x+4 = 34

The width is 15 feet, the length is 34 feet.

Verifying, you have 15+15+34+34 = 98