How do you prepare 0.05 M Zinc chloride?

To prepare a 0.05 M solution of zinc chloride (ZnCl₂), first calculate the amount of zinc chloride needed by using the formula: mass (g) = molarity (M) × volume (L) × molar mass (g/mol). The molar mass of ZnCl₂ is approximately 136.3 g/mol, so for 1 liter of a 0.05 M solution, you would need 6.815 g of ZnCl₂. Dissolve this amount in distilled water, and then dilute the solution to a final volume of 1 liter. Always ensure to mix thoroughly and label the solution appropriately.