How many F atoms are in 12.15 mol of C2HBrClF3?

In one mole of C₂HBrClF₃, there are three fluorine (F) atoms. Therefore, to find the total number of F atoms in 12.15 mol of C₂HBrClF₃, you multiply the number of moles by the number of F atoms per mole: (12.15 , \text{mol} \times 3 , \text{F atoms/mol} = 36.45 , \text{F atoms}). Thus, there are 36.45 moles of F atoms in 12.15 mol of C₂HBrClF₃.