If two consecutive sides of a rhombus are represented by 3x - 6 and x plus 14 then the perimeter of the rhombus is what?

Answer:

96

Step-by-step explanation:

we know that in a rhombus all the sides are equal so,

x+14 = 3x - 6

=> 2x = 20

=> x = 10

so putting x in (x+14)

we get the side is equal to 24

perimeter = 4*(side)

= 4*24

=96