Yes, they are.
Sketch of proof:
Odd square root is a number x of form x = 2n + 1.
Square of this root is:
x2=(2n+1)2=4n2+4n+1=y,
which can be expressed as:
y=2(2n2+2n)+1.
Let t = 2n2+2n.
Then,
y=2t+1, which is an odd number.
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