Is a gas sample of 67 L is collected at 194 KPa what is the volume of the gas at 75 KPa?

To find the new volume of the gas at 75 kPa, you can use Boyle's Law, which states that ( P_1 V_1 = P_2 V_2 ). Here, ( P_1 = 194 ) kPa, ( V_1 = 67 ) L, and ( P_2 = 75 ) kPa. Rearranging the equation to solve for ( V_2 ) gives:

[ V_2 = \frac{P_1 V_1}{P_2} = \frac{194 , \text{kPa} \times 67 , \text{L}}{75 , \text{kPa}} \approx 173.33 , \text{L}. ]

Thus, the volume of the gas at 75 kPa would be approximately 173.33 L.