Find the length of the missing side of each right triangle to the nearest tenth legs of 4 cm and 6 cm leg of 9 m hypotenuse of 15 m leg of 36 ft hypotenuse of 39 ft legs of 28 cm and 45?

# 4 and 6 give a hypotenuse of √(42 + 62) = √(16 + 36) = √52 = 7.2111 = 7.2 to nearest tenth. # 9 and X give a hypotenuse of 15 so 152 = 92+ X2 which gives 225 = 81 + X2 which gives 144 = X2 which gives 12 = X # 36 and Y give a hypotenuse of 39 so 392 = 362+ Y2 which gives 1521 = 1296 + Y2 which gives 225 = Y2 which gives 15 = Y # 28 and 45 give a hypotenuse of √(262 + 452) = √(676 + 2025) = √2701 = 51.9711 = 52 to the nearest tenth.