How do i find the largest angle with consecutive integers on a pentagon?

The sum of all interior angles of a polygon with n sides is 180 degrees × (n - 2), so the sum of all angles within a pentagon is 540 degrees (180 x (5 - 2) = 180 x 3 = 540). The five interior angles of a pentagon then must have an average of 108 degrees each (540 / 5 = 180), and the angles having consecutive integers will be 106, 107, 108, 109, and 110 degrees. The largest angle will be 110 degrees.